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Code d'Examen: 000-183
Nom d'Examen: IBM (IBM WebSphere Mesage Broker V7.0, Solution Development)
Questions et réponses: 114 Q&As
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NO.1 Which one of the following advantages does the Enterprise Service Bus deliver over traditional
point-to-point solutions?
A.Scalability
B.Adaptability
C.Redundancy
D.Performance
Answer: B
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NO.2 The solution developer has been informed by the SAP team that the userid and password for the SAP
test environment needs to be replace
D.What is the EASIEST way to reconfigure userid and password for an SAP EIS adapter?
A.Modify the deployment descriptor in the affected bar files and redeploy them to all required locations.
B.Use the following command against the affected broker(s): mqsisetdbparms <brokername> -n
eis::<adaptername> -u <username> -p <password>
C.Use the following command against the affected broker(s): mqsichangeproperties <brokername> -c
eis::<adaptername> -o SAP -u <username> -p <password>
D.Rerun the Adapter Connection Wizard for the component, enter the updated values and redeploy the
component to all required locations.
Answer: B
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NO.3 In a message flow, a developer needs to enrich an employee's record with information from a
database.Consider this input message.
Which of the ESQL statements in the response options will produce the following output message?
A.SET OutputRoot.XMLNSC.Employee.Name[] = (SELECT ITEM E.EmpName from Database.Employee
as E where E.EmpNumber = InputBody.Employee.Number);
B.SET OutputRoot.XMLNSC.Employee.Name[] = (SELECT E.EmpName AS Name from
Database.Employee as E where E.EmpNumber = InputBody.Employee.Number);
C.SET OutputRoot.XMLNSC.Employee = THE(SELECT E.EmpName from Database.Employee as E
where E.EmpNumber = InputBody.Employee.Number);
D.SET OutputRoot.XMLNSC.Employee = THE(SELECT ITEM E.EmpName AS Name from
Database.Employee as E where E.EmpNumber = InputBody.Employee.Number);
Answer: A
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NO.4 View the Exhibit:
The above flow processes a large incoming file line by line once every four hours.Performance is
unsatisfactory even though the server has spare memory and unused processors.Configuring additional
instances does not improve this.The following pair of flows was suggested by an architect.The first flow
will slice the incoming file into messages without any further processing, which is to be done by the
second flow.
What is the expected outcome if the second flow is configured with a large number of additional
instances?
A.Throughput will improve somewhat.Message sequence will not be affected.
B.Throughput will be unaffecte
D.Message sequence will most likely be affected.
C.Throughput will improve significantly.Message sequence will most likely be affected.
D.Throughput will deteriorate slightly due to the extra queuing.Message sequence will not be affected.
Answer: C
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NO.5 A developer has a message flow that consists of an MQInput node, Compute node and MQOutput
node.The message is parsed by the XMLNSC domain.The Compute node will extract the name and age
of each player, then send them onto the register players application to have the team registered.The input
message that the Compute node will be processing is shown below.
What MUST be done to access the information from the first player?
A.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputBody.Body.Player[1]
B.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputBody.DetailedMsg.Body.Player[1]
C.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[0]C.Set
OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[0]
D.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[1]D.Set
OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[1]
Answer: B
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NO.6 Consider the following ESQL code snippet from a Compute node.
What is the value of OutputRoot.XMLNSC?
A.NULL
B.<Winner/>
C.<Winner Name="Robert"/>
D.<Winner><Name>Rocky</Name></Winner>
Answer: D
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NO.7 A developer needs to create an asynchronous messaging application to connect to a third party which
uses a programming interface known as Message Queue Interface (MQI).Which transport protocol should
the developer use?
A.MQ
B.FTP
C.JMS
D.XMS
Answer: A
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NO.8 A developer is tasked with designing a message flow, utilizing an XSLTransform node.Which location is
searched first by the broker, to determine the name of the style sheet to use?
A.The LocalEnvironment.
B.The BAR file overrides.
C.The XSLTransform node properties.
D.Inside the message XML data.
Answer: D
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NO.9 A message flow reads a file, record by record.Based on the content of each record, it will be propagated
to one or more output queues.The File Input node has the Transaction property set to yes and all output
nodes are configured to be Automatic node has the transaction property set to yes and all output nodes
are configured to be automatic In the event that flow execution is interrupted by a hardware failure, which
one of the following is true?
A.Processing will resume at the beginning of the file; previously created messages will be duplicated.
B.Processing will resume at the beginning of the file; previously created messages will be backed out.
C.Processing of the file resumes at the last checkpoint; any extraneous messages will have been rolled
back.
D.The file will be deleted or archived depending on the setting of the File Input node; unprocessed
records will be missing from the output.
Answer: A
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NO.10 Which Message Broker artifact type is not analyzed by Impact Analysis?
A..esql
B..mset
C..msgmap
D..msgflow
Answer: B
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NO.11 As part of an Order Process flow, a developer must add a new section to an existing XML message.The
relevant section of the incoming message is as follows:
The developer must add the following Order Item, to fall in the correct numeric sequence: <OrderItem>
<Number>333</Number> </OrderItem> How would the developer achieve this?
A.DECLARE FieldRef REFERENCE TO OutputRoot; CREATE FIELD
OutputRoot.XMLNSC.OrderMsg.OrderItem[3].Number AS FieldRef; SET FieldRef = '333';
B.DECLARE FieldRef REFERENCE TO OutputRoot.XMLNSC.OrderMsg.OrderItem[2]; CREATE
NEXTCHILD OF FieldRef NAME 'Number'; SET FieldRef = '333';
C.DECLARE FieldRef REFERENCE TO OutputRoot.XMLNSC.OrderMsg.OrderItem[2]; CREATE
NEXTSIBLING OF FieldRef NAME 'OrderItem'; SET FieldRef.Number = '333';
D.DECLARE FieldRef REFERENCE TO OutputRoot.XMLNSC.OrderMsg.OrderItem[2]; CREATE
NEXTSIBLING OF FieldRef AS FieldRef NAME 'OrderItem'; SET FieldRef.Number = '333';
Answer: D
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NO.12 A customer needs to dynamically choose which web service URL to call from a WSDL in the
WebSphere Service Registry and Repository (WSRR), based on a company acronym in the input
message received by Message Broker.Which node should the solution developer choose when
implementing this type of retrieval operation?
A.EndpointLookup
B.RegistryLookup
C.EndpointRetrieval
D.DatabaseRetrieval
Answer: A
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NO.13 A developer needs to call a request/response web service from a message flow.Knowing response
messages may not arrive in the same order as the requests, what set of processing nodes will
automatically set the required WS-Addressing standard that assures message correlation?
A.SOAPInput and SOAPReply
B.SOAPExtract and SOAPReply
C.SOAPRequest and SOAPReply
D.SOAPAsyncRequest and SOAPAsyncResponse
Answer: D
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NO.14 A developer needs to generate a monotonically increasing sequence number for each message in a
given message flow.What is the MOST efficient way to achieve this?
A.Use the Create Sequence operator of ESQL.
B.Use the Generate Sequence operator of Java.
C.Use the Sequence function of an external database.
D.Use the Sequence node of WebSphere Message Broker.
Answer: D
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NO.15 Consider the following two implementations of a request/response pattern.1) Asynchronous with a
separate flow for the response logic using an MQInput node
2)
Synchronous, completing the round trip in the same flow pulling the response message with an MQGet
node
Which of the following is FALSE?
A.Multiple flow instances will not help throughput in either implementation.
B.The synchronous implementation will require more memory, especially in scenarios with large
messages and high throughput requirements.
C.Given sufficient resources, the synchronous implementation will perform better in cases where large
amounts of data (i
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